OK, if 'dollar' is simply an alias for the function name "$", then that seems
like it is a reasonable approach...
However, I would implement this in R by defining an R function named dollar in
an R package, rather than having rpy2 do a translation.
The current approach effectively blocks users from access data objects named
'dollar' via the r.dollar syntax. If dollar was a function defined as
dollar <- .Primitive("$")
Then the current syntax would continue to work, while still allowing a user to
do
r("dollar <- 1")
in which case
r.dollar
would return the R vector containing 1, and
stackloss.r.dollar("Air.Flow")
would still work, too.
-Greg
> -----Original Message-----
> From: [email protected] [mailto:[email protected]] On Behalf Of Nathaniel
> Smith
> Sent: Thursday, October 01, 2009 4:15 PM
> To: Warnes, Gregory R.
> Cc: RPy help,support and design discussion list
> Subject: Re: [Rpy] na.action?
>
> On Thu, Oct 1, 2009 at 10:48 AM, Warnes, Gregory R.
> <[email protected]> wrote:
> > These are the longstanding rpy rules (where 'x' represents any
> sequence
> > of valid name character in *python*, including A-Z, a-Z anywhere and
> 0-9
> > anywhere except in the first position):
> >
> > python R Example
> > x_x x.x print_default(m) --> print.default(m)
> > x_ x print_(m) --> print(m)
>
> Heh -- convergent evolution, then, since I never actually used
> "classic" rpy.
>
> > However, the (proposed?) translation of 'dollar' to '$' seems
> > problematic to me, since the string/word 'dollar' can reasonably be
> > expected to appear in variable names.
> >
> > What do you have in mind for that?
>
> NB: I just double-checked the code, and it's specifically if the name
> equals "dollar" exactly then it is translated to "$" -- names that
> merely contain "dollar" as a substring are unaffected.
>
> I think this meets the definition of a "miswart":
> http://www.websters-online-dictionary.org/mi/miswart.html
> it's ugly looking, but in practice the ability to conveniently access
> columns from data frames, etc., outweighs the ugliness. (Of course, if
> anyone has an even *better* idea for how to do this, I'd love to hear
> it. Typing "dollar" is somewhat ridiculous. I just couldn't deal with
> typing r["$"] all the time for such a fundamental operation.)
>
> The way it looks in practice:
> R: stackloss$Air.Flow
> Python (rnumpy-style): stackloss.r.dollar("Air.Flow")
>
> -- Nathaniel
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