Tomer, 

Thanks for the quick response!   That was exactly my problem. 

-Mark

On Wednesday, May 8, 2013 4:00:40 AM UTC-7, Tomer Filiba wrote:
>
> you need to pass a service class, not an instance.
> see 
> https://groups.google.com/forum/?hl=en_US&fromgroups=#!searchin/rpyc/service$20arguments/rpyc/AMwdklcRzFA/S7-mf1oqiH4J
>
>
> -tomer
>
>
>
>
> -----------------------------------------------------------------
>     
> *Tomer Filiba* 
> tomerfiliba.com     <http://www.facebook.com/tomerfiliba>    
> <http://il.linkedin.com/in/tomerfiliba> 
>
>
> On Wed, May 8, 2013 at 8:42 AM, Mark <[email protected] 
> <javascript:>>wrote:
>
>> I am trying to create my own Service using python 2.7 and RPyC 3.2.3.  
>> I have removed any customl functions and create a service using the 
>> following syntax:
>>
>> class MyService(rpyc.Service):
>>       # stripped out all my functions for now
>>
>> # start the service
>> t = ThreadedServer(MyService(args.name), port = int(port)) #passed as a 
>> parameter
>>
>> t.start()
>>
>> #################
>>
>> I then try to connect to this service simply via:
>>
>> rpyc.utils.factory.connect('localhost',int(replicaPort))
>>
>> I have also tried:
>>
>> rpyc.connect('localhost',int(port),MyService    
>>
>> rpyc.connect('',int(port))   
>> and a number of other variations, but they all give me back the same 
>> error:
>>
>> TypeError  'MyService' object is not callable.
>>
>> Does anyone know why this is happening or have any suggestions as to how 
>> I can troubleshoot this error?  Thanks in advance!
>>
>> -Mark
>>
>>
>>
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