I have two machines using python rpyc ,one is server(ip:10.0.3.120),
another is client(ip:10.0.3.197). The code shows below:
*Server* (ip:10.0.3.120)
from rpyc import Servicefrom rpyc.utils.server import ThreadedServer
class TestService(Service):
def exposed_test(self, num):
return num + 1
sr = ThreadedServer(TestService, port=9999, auto_register=False)
sr.start()
*Client* (ip:10.0.3.129)
import rpyc
conn = rpyc.connect('10.0.3.120', 9999)
cResult = conn.root.test(11)
conn.close()
print cResult
Client shows this error when I run server and client:
Traceback (most recent call last):File "rpyc_client.py", line 4, in <module>
conn = rpyc.connect('10.0.3.120', 9999)File
"/usr/local/lib/python2.7/site-packages/rpyc-3.2.3-py2.7.egg/rpyc/utils/factory.py",
line 89, in connect
s = SocketStream.connect(host, port, ipv6 = ipv6)File
"/usr/local/lib/python2.7/site-packages/rpyc-3.2.3-py2.7.egg/rpyc/core/stream.py",
line 114, in connectreturn cls(cls._connect(host, port, **kwargs))File
"/usr/local/lib/python2.7/site-packages/rpyc-3.2.3-py2.7.egg/rpyc/core/stream.py",
line 92, in _connect
s.connect((host, port))File "/usr/local/lib/python2.7/socket.py", line 224, in
methreturn getattr(self._sock,name)(*args)
How does connect method use? If I use public network IP to build a rpyc server,
could I connect it at home ?? Thanks a lot!
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