> I'm 99 44/100% sure that you have it right. The expression x != y is > syntactic sugar for !(x == y) much like x += y is syntactic sugar for > x = (x +y) > > The parser turns these into an internal representation (abstract > syntax tree for 1.8, byte-codes for 1.9) which is identical to the > second form. >
In 1.8 it's just syntactic sugar. But 1.9 provides actual != and !~ methods so that you can override it in situations like this. (from Ruby-Core: http://www.ruby-forum.com/topic/134608 ) _______________________________________________ rspec-users mailing list rspec-users@rubyforge.org http://rubyforge.org/mailman/listinfo/rspec-users
