On Jul 13, 2009, at 1:46 PM, Scott Taylor wrote:
On Jul 13, 2009, at 1:32 PM, Adam Anderson wrote:
Thanks for the reply, Scott.
What you describe is what is currently being done.
now = Time.now
Time.stub!(:now).and_return(foo_time)
do_stuff
Time.stub!(:now).and_return(now)
However, this is not returning the actual time it is only returning
the time set on the first line. I need Time.now to return to its
original behavior (i.e., returning the current, actual time).
Well, every time you create a stub, rspec aliased the method before
it destroys it:
http://gist.github.com/1ed96143092a02cb727b
It's ugly, but it will work.
Here's another solution, without needing to resort to the library:
http://gist.github.com/e573cb79073805a632c9
Of course, this solution only works if you don't have other stubs on
Time.
Scott
You might also want to check out this library:
http://github.com/notahat/time_travel/tree/master
Scott
-Adam
On Mon, Jul 13, 2009 at 9:58 AM, Scott Taylor
<sc...@railsnewbie.com> wrote:
On Jul 13, 2009, at 12:09 PM, Adam Anderson wrote:
I can't seem to find a good way to do this. If I stub out Time.now
in one of my specs but need to return it to its original
functionality then can I remove the stub?
So I'd like to say something like:
Time.stub!(:now).and_return(foo_time)
Time.now # => foo_time
Time.unstub!(:now)
Time.now # => whatever time it actually is
Capture it before you stub it:
real_now= Time.now
Time.stub!(:now).and_return a_later_time
Time.stub!(:now).and_return real_now
Is this possible? I noticed $rspec_mocks.reset_all, but obviously I
don't want everything to go away, just this one stub.
-Adam
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