On Aug 9, 2010, at 10:06 AM, Rick DeNatale wrote:
> On Mon, Aug 9, 2010 at 8:49 AM, David Chelimsky <dchelim...@gmail.com> wrote:
>>
>> On Aug 9, 2010, at 7:38 AM, Ashley Moran wrote:
>>
>>> Hi
>>>
>>> I was just about to replace a `before` block along the lines of:
>>>
>>> before(:each) do
>>> @cti_b_id = service.create(name: "Item-B")
>>> @cti_z_id = service.create(name: "Z-Item")
>>> @cti_a_id = service.create(name: "Item-A")
>>> # ...
>>> end
>>>
>>> with
>>>
>>> let!(:cti_b_id) { ... }
>>> let!(:cti_z_id) { ... }
>>> let!(:cti_a_id) { ... }
>>>
>>> But then I wondered - since the spec depends on the order they are created
>>> in (it proves ordering is independent of creation order) - is the run order
>>> of `let!` guaranteed? I imagine they run in the order I expect (ie top to
>>> bottom), but I wondered if that was an explicitly stated property of RSpec?
>>
>> Yes, eval'd in order. No, not explicitly stated, but I think it should be.
>> Want to submit a patch with a spec for this?
>
> But,
>
> First of all, what's let! as opposed to let, I can't seem to find it
> via google or the latest draft of the book.
http://rdoc.info/projects/rspec/rspec-core - search for let and let!
>
> Second, unless let! is a new method which not only defines the
> memoized method but invokes it
That's what it is. Sort of. It gets invoked by an implicit before hook which is
added - those get eval'd in the order in which they get defined.
> , then the order of evaluation will
> depend on the order the generated let methods are invoked in the
> example won't it?
>
>
> --
> Rick DeNatale
>
> Blog: http://talklikeaduck.denhaven2.com/
> Github: http://github.com/rubyredrick
> Twitter: @RickDeNatale
> WWR: http://www.workingwithrails.com/person/9021-rick-denatale
> LinkedIn: http://www.linkedin.com/in/rickdenatale
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