&:self won't work because self isn't an instance method on the object, eg.
some_object.self won't work either.
If you wan't something cleaner couldn't you use this method in spec_helper.rb ?
def block_yield(object, method)
object.send(method) { yield if block_given? }
end
Then:
block_yield(thing, :do_stuff).should == "value"
Mvh
Morten Møller Riis
On Mar 7, 2012, at 9:42 PM, David Chelimsky wrote:
> On Wed, Mar 7, 2012 at 2:32 PM, Matt Wynne <[email protected]> wrote:
>>
>> On 7 Mar 2012, at 18:16, David Chelimsky wrote:
>>
>> On Wed, Mar 7, 2012 at 11:56 AM, Matt Wynne <[email protected]> wrote:
>>
>>
>> On 7 Mar 2012, at 11:39, Morten Møller Riis wrote:
>>
>>
>> On Mar 7, 2012, at 8:22 AM, Matt Wynne wrote:
>>
>>
>>
>> Hi all,
>>
>>
>> I'm spec'ing a method that yields a value. Right now, I spec it like this:
>>
>>
>> result = nil
>>
>> thing.do_stuff { |value| result = value }
>>
>> result.should == expected
>>
>>
>> This feels like too much ceremony. What I want to do is something more this:
>>
>>
>> thing.do_stuff.should yield_value(expected)
>>
>>
>> Is there anything built into RSpec to let me do this? If not, how do other
>>
>> people test yields?
>>
>>
>> cheers,
>>
>> Matt
>>
>>
>>
>> How about this?
>>
>>
>> thing.do_stuff(&:to_s).should == expected
>>
>>
>>
>> Yes, that's a neat hack, but I'd prefer to be able to assert on the actual
>>
>> yielded value, instead of the result of calling an arbitrary method on it.
>>
>>
>> thing.do_stuff(&:self) would be a bit less arbitrary :)
>>
>>
>> It would, but does it work?
>>
>> I assumed it would too but here on my Ruby 1.9.2 it gives me a NoMethodError
>> :(
>
> I had assumed as well, and you know what they say about ASSuming!
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