Can you provide a more concrete example? In general, this would make me a
bit uneasy about what is either being tested or how the system is joined
together.
If you there are no side effects and you just have a basic value, why not
just stub the basic return?
class Foo
def hello
:foo
endend
it do
f = Foo.new
allow(f).to receive(:hello).and_return(:foo, nil)
expect(f.hello).to be :foo
expect(f.hello).to be nil
expect(f.hello).to be nil
end
If there are no side effects, but something needs to be calculated first,
possibly call it first?
it do
f = Foo.new
allow(f).to receive(:hello).and_return(f.hello, nil)
expect(f.hello).to be :foo
expect(f.hello).to be nil
expect(f.hello).to be nil
end
Otherwise, it's probably best for you to fall back to Ruby and just define
a singleton method:
it do
f = Foo.new
f.define_singleton_method(:hello) do
return if @already_called
@already_called = true
super() # parens are necessary to make Ruby happy
end
expect(f.hello).to be :foo
expect(f.hello).to be nil
expect(f.hello).to be nilend
Maybe someone else has some other ideas here.
On Fri, May 16, 2014 at 2:18 AM, Panayotis Matsinopoulos <
[email protected]> wrote:
> Hi,
>
> Is there a way that I can stub all the calls to a method except from the
> first one?
>
> Example:
>
> class Book
> def foo
> "Book#foo()"
> end
> end
>
> In spec:
>
> it 'x' do
> # .... (do something to stub all but the first method call to
> `Book#foo`)....
>
> b = Book.new
> expect(b.foo).to eq('Book#foo()')
> expect(b.foo).to be_nil
> expect(b.foo).to be_nil
> end
>
> Thanks in advance
> Panayotis
>
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