On Thu 01 Sep 2005, Xuehai Zhang wrote:
> >
> > If (similar) tasks are run in parallel, then the data of the files being
> > handled may still be in the buffer cache so that it doesn't need to get
> > read in from disk again. This will save time...
> 
> I agree with you that caching effect might be the cause. The buffer cache
> you mentioned refers to the cache on the data source, right?

Yes.


Paul Slootman
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