Thanks a lot, i thought it was more difficult, but it seems not a lot.
I would like to know also, how it could be the rtlinux module. Because
all examples i have seen are about periodic task or so. And this it
won't be like this, isn't it? I'm talking about the inicialization of
the rttask and what i need to it.
Thank you for understanding that i am starting with this.
Marc LE DOUARAIN escribio:
>
> You haven't to use FIFO to pass address if you use mbuff to share memory...
>
> A little example :
>
> You can create a structure like this to share it later from the 2 sides (RT and
>Linux) :
> struct StructDataShared
> {
> char PictureData[xxxx];
> int FlagNewPicture;
> }
>
> - In Linux process, you have :
> -----------------------------------------------
> volatile StructDataShared * PtrDataShared;
> At the start:
> PtrDataShared = (StructDataShared *) mbuff_alloc("example",yyyy);
>
> At the end :
> mbuff_free("example",(void *)StructDataShared);
> For use, fill the PictureData, then when done :
> PtrDataShared->FlagNewPicture = 1; /* to tell RT side, there is a new picture
>available */
>
> - In RT, you have :
> ------------------------------
> volatile StructDataShared * PtrDataShared;
> In init_module()
> PtrDataShared = mbuff_alloc("example",yyyy);
> In cleanup_module()
> mbuff_free("example",PtrDataShared);
> Then you look the flag PtrDataShared->FlagNewPicture to see if there is a new
>picture available, when read
> PtrDataShared->FlagNewPicture = 0; /* To indicate RT process 've read the new
>picture */
>
> >>> [EMAIL PROTECTED] 12/06/01 15h33 >>>
> Now , how i understand, the things will be like following.
> -First i push my image in linux space, locating it in shared memory by
> mbuff.
> -After, i pass with a FIFO the adress of the image in memory to the
> rttask. Please tell me if it's the good way.
> -Now, the rttask can work. In fact there is a doubt that i have here.
> The rttask will be in memory waiting for the data in the FIFO. When it
> recives this data, it will be start to work. How i have to do to work
> by this way.
> I am not clear in this way. One example easy that i want to do is for
> example to acces from the rttask to the image and pass it to negative,
> and after the linux task could access to it. The image will be
> actualized often, because is video acquisition. If someone knows any
> similar application or the way i can make , i will be agreed.
>
> Marc LE DOUARAIN escribio:
> >
> > To share data between RTTask and ClassicTask the easiest is using MBUFF.
> > It's already given whith RTLinux3 (in drivers/) and it's really easy to use. Look
>at examples !
> >
> > >>> [EMAIL PROTECTED] 11/06/01 15h41 >>>
> > I have an image in a buffer in a linux program. I would like to access
> > it with a rtlinux program for treating it. How i could make it?
> > How the rttask could access to the sam e buffer as the linux
> > task?(passing only the adress number with a fifo or something like this)
> > or maybe it's necessary to push it in a array?
> > Please answer if somebody knows.
> > Thank you..
> >
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