Use pthread_kill(thread,RTL_SIG_WAKEUP) instead of wakeup_np.
Wakeup_np will call the scheduler and, if the current thread is lower
priority, it will switch !
Remember, a signal/interrupt handler executes in the context of
the running thread, whatever that is.
On Tue, Apr 25, 2000 at 10:56:06AM +0200, [EMAIL PROTECTED] wrote:
>
> I found a strange thing.
>
> I have a hardware IRQ handler that wakes up a sleeping task:
>
> it_handler(.....)
> {
> ...
> rtl_printf("checkpoint 1\n");
> if (waiting_thread) pthread_wakeup_np(waiting_thread);
> rtl_printf("checkpoint 2\n");
> ...
> }
>
>
> user_thread(...)
> {
>
> ...
> rtl_no_interrupts(flags);
> waiting_thread = pthread_self();
> pthread_make_periodic_np(waiting_thread, sometime, 0);
> pthread_wait_np();
> rtl_printf("checkpoint 3\n");
> waiting_thread = NULL;
> rtl_restore_interrupts(flags);
> ...
> }
>
> Diagnostic printf-s show that the executing order is 1-3-2.
> This means, that priority of interrupt handler thread is not
> definitely higher than priority of the normal thread.
> When pthread_wakeup_np() reschedules threads, user_thread
> gets the control instead of it_handler.
>
> I could accept this if priority of an IRQ handler would be _well-known_
> or could be set.
> But in lack of documentation one may think that it has
> the highest possible priority and no user created threads can beat it.
>
> What is the matter?
>
> Gabor
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--
---------------------------------------------------------
Victor Yodaiken
FSMLabs: www.fsmlabs.com www.rtlinux.com
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