For the benefit of other newbies:
The reason it only worked in the else branch is because you can't have
the following hash:
{ :condition => nil, "I am a block" }
On Sat, Oct 20, 2012 at 5:35 PM, Eric Sagnes <[email protected]> wrote:
> Beginners error...
>
> After digging a little I found a solution.
> Encapsulating the :block in another variable to isolate them in a single hash
> fixed the problem.
>
>
> On 2012年10月21日 日曜日 01:15:26 Eric Sagnes wrote:
>> Hello,
>>
>> I just started to play with Parslet, and I must say it is very intuitive.
>> Coding a parser was a breeze, but I am having some trouble with the
>> transform part.
>>
>> I made a simple if else conditional parser, and I can't get the transform to
>> work.
>>
>> Here the input:
>> '$if(foo)$ foo_block $elsif(bar)$ bar block $else$ baz $endif$'
>>
>> And the parser result is:
>> {:text=>
>> [{:conditional=>
>> {:if_expression=>
>> {:condition=>{:attribute=>{:attribute_atom=>"foo"@4}},
>>
>> :block=>" foo_block "@9},
>> :
>> :elsif_expression=>
>>
>> [{:condition=>{:attribute=>{:attribute_atom=>"bar"@27}},
>>
>> :block=>" bar block "@32}],
>> :
>> :else_expression=>{:block=>" baz "@49}}}]}
>>
>> So far, so good.
>>
>> I made a test rule to transform the :block value into some text
>> rule(:block => simple(:block) ){ "I am a block" }
>>
>> And I got the following result
>> {:text=>
>> [{:conditional=>
>> {:if_expression=>{:condition=>nil, :block=>" foo_block "@9},
>>
>> :elsif_expression=>[{:condition=>nil, :block=>" bar block "@32}],
>> :else_expression=>"I am a block"}}]}
>>
>> Only the else_expression :block get transformed, what am I missing to have
>> the
>> :elsif_expression :block and :if_expression :block also transformed?
>>
>> Thanks in advance,
> --
> Eric Sagnes
> サニエ エリック
