Heya,
thanks. I think i was having a slow day. I didn't even think to try
value.something()!!!! It seems a little odd that you get back the pair
when iterating, and not the value, given that the point of a hash is
retreiving the values by key or iteration overall).
Atleast its now here and documented a little more clearly for all to
read!!
Emma xx
On May 21, 7:41 am, Christophe Porteneuve <[EMAIL PROTECTED]> wrote:
> Hey Emma,
>
> What exactly do you call a hash? A *Hash* instance? Or just a good ol'
> JavaScript object? Or even an Array, perhaps?
>
> Now, if you're indeed using a Hash, look at the docs to see that
> enumerating a hash gets the *pairs*, not the values alone. So you'd
> need to access the pair's 1-indexed property, or "value" property
> (they're basically the same, in two notations), and call your method on it.
>
> var h = new Hash();
> h['john'] = new Player('john');
> h['mary'] = new Player('mary');
>
> h.each(function(pair) { pair[1].something(); });
> // or:
> h.each(function(pair) { pair.value.something(); });
>
> Because of this, invoke won't work as expected, since it requires the
> invoked method to be present in the passed object. But you can trick it:
>
> h.pluck('value').invoke('something');
>
> Check out the docs for these:
>
> http://prototypejs.org/api/hash/each
> http://prototypejs.org/api/enumerable/invoke
> http://prototypejs.org/api/enumerable/pluck
>
> 'HTH,
>
> --
> Christophe Porteneuve a.k.a. TDD
> "[They] did not know it was impossible, so they did it." --Mark Twain
> Email: [EMAIL PROTECTED]
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