You... can't. That's a limitations of JavaScript.
On Nov 19, 6:45 pm, redheat <[EMAIL PROTECTED]> wrote:
> Okay... how do I get the name of the superclass from within the class?
> For example: how can I tell from within the Dog Class that Dog is a
> subclass of Animal. How can I get the name "Animal" without using
> instanceof?
>
> Edd
>
> On Nov 19, 2:05 pm, "Nicolás Sanguinetti" <[EMAIL PROTECTED]> wrote:> You
> have to call it on the Class, not the instances, and the "klass()"
> > returned works fine. With your example:
>
> > var duck = new (Dog.superclass)("ducky");
> > duck instanceof Animal
>
> > >>> true
>
> > Best,
> > -Nicolas
>
> > On Nov 19, 2007 11:59 AM, redheat <[EMAIL PROTECTED]> wrote:
>
> > > Any ideas why I only get "klass()" returned when I try to access
> > > ClassName.superclass or ClassName.subclasses, and "undefined" when I
> > > access class_instant.superclass or class_instant.subclasses?
>
> > > I'm probably doing something really stupid.
>
> > > var Animal = Class.create({
> > > initialize: function(name) {
> > > this.name = name;
> > > }
> > > });
>
> > > var Dog = Class.create(Animal, {
> > > initialize: function($super, name) {
> > > $super(name);
> > > },
>
> > > bark: function() {
> > > return this.name + ' said "Woof!"';
> > > }
> > > });
>
> > > var poodle = new Dog('Jack');
> > > poodle.superclass; //--> undefined
> > > Dog.superclass; //--> klass()
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