I'm not sure why you need to call $.
I'm also seeing identical results when using sub('.', ',') and
sub('\.', ',')
- kangax
On Apr 9, 9:04 am, Dan <[EMAIL PROTECTED]> wrote:
> Hello.
>
> I tried this:
>
> var s = $(new String("1234,5678"));
>
> s = s.sub("." , ","); // gives ".234,5678" this is ok, becaus . is a
> regex char
> s = s.sub("\.", ","); // gives the same output as input, i think this
> isnt correct, the point should be comma
>
> Does i oversee anything?
> Bye!
> Dan
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