$$('span.' + currentHighlightGroup);
// or
$$('span').findAll(function(el){
return el.hasClassName(currentHighlightGroup)
});
// the latter one will actually be much slower...
- kangax
On Apr 28, 2:42 pm, "[EMAIL PROTECTED]"
<[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I want the $$() method to take the selector as an variable. See
> below, I am trying to pass the class name as javascript variable so I
> can write a generic function in my application but $$() returns
> nothing for the following line
>
> var currentHightLightGroup ="amountsFields";//This one comes as a
> function parameter
> $$('span[class=\''+currentHightLightGroup+'\']')
> -> returns nothing.
>
> Any help is much appericated.
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