On May 6, 8:09 pm, ahseed <[EMAIL PROTECTED]> wrote:
> Hi Matt,
>
> I'm trying to compare values to avoid a person to be present twice in
> the list !
>
> I've already tried the $F function with no success...
> Trying your code (putting in an array) give me (with 3 iteration)
>
> var arr = [];
> // countUser == 3 and input fields are filled with firstname and
> lastname
You mean countUsers = 3
> for(var i = countUsers; i > 0; i--) {
Above you used countUser, here it is countUsers - a typo perhaps? The
above will iterate over elements with id's username[3], username[2]
and username[1], is that what you want?
> arr.push($F("username["+countUsers+"]"));}
The value being decremented is i, not countUsers, so:
arr.push($F("username["+ i +"]"));}
> alert(arr);
>
> > ,, <
>
> I just tried to do this :
>
> alert($F("username[1]")); and then it works !!!
>
> So the problem could come from the type of iterator, should it be a
> string...
Array indexes are strings, however javascript will convert whatever
you provide as an index to a string. There is no need to use say:
arr['3']
rather than
arr[3];
and the second is more efficient.
> Trying to force a string before passing the argument as below
>
> var arr = [];
> // countUser == 3 and input fields are filled with firstname and
> lastname
> for(var i = countUsers; i > 0; i--) {
> var myCounter = new String(countUsers);
That will create a String object, not a string primitive. If
conversion to a string was required (and it isn't) it's more efficient
to use:
var myCounter = '' + i;
i.e. use string concatenation and javascript's automatic type
conversion to generate a string variable.
> arr.push($F("username["+myCounter+"]"));}
>
> alert(arr); > SAME RESULT !
Because that wasn't the problem.
--
Rob
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