Gareth,
I believe #replace should be able to do this just fine.
-- kangax
On Jul 1, 8:44 pm, "Gareth Evans" <[EMAIL PROTECTED]> wrote:
> 1) get a reference to your tr (for example using
> table.select('tr:nth-child(4)').reduce() )
> 2) use tr.insert({before: new Element('tr').insert(new
> Element('td').update('hai')) }); //or variant of insert with innerhtml
> content from ajax request
> 3) tr.remove();
>
> On Wed, Jul 2, 2008 at 12:24 PM, kermit <[EMAIL PROTECTED]> wrote:
>
> > Hi,
>
> > Hopefully a quick example will illustrate what I'm trying to do.
>
> > <table>
> > <tr>
> > <td>test</td>
> > <td>test</td>
> > </tr>
> > <tr>
> > <td>row 2</td>
> > <td>row 2</td>
> > </tr>
> > <tr>
> > <td>row 3</td>
> > <td>row 3</td>
> > </tr>
> > </table>
>
> > Using AJAX, I'd like to be able to replace an entire <tr> block, for
> > example to give:
>
> > <table>
> > <tr>
> > <td>test</td>
> > <td>test</td>
> > </tr>
>
> > </table>
> > <p>This is dynamic content</p>
> > <table>
>
> > <tr>
> > <td>row 3</td>
> > <td>row 3</td>
> > </tr>
> > </table>
>
> > I (wrongly) assumed the solution would just be:
>
> > <table>
> > <tr>
> > <td>test</td>
> > <td>test</td>
> > </tr>
> > <div id='mycontent'>
> > <tr>
> > <td>row 2</td>
> > <td>row 2</td>
> > </tr>
> > </div>
> > <tr>
> > <td>row 3</td>
> > <td>row 3</td>
> > </tr>
> > </table>
>
> > ... then use AJAX to replace the contents of the 'mycontent' div.
> > Unfortunately when this renders (in Firefox anyway), the div is placed
> > outside of the table (above it), so any content written to the div
> > also appear outside of the table (I confirmed the position of the div
> > by putting a border around it). Perhaps this is to be expected since
> > in standard HTML the div shouldn't be where it is.
>
> > So my question is how I can achieve this replacement of the table row
>
> > Best,
> > Mark
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