Hi!

Take a look at:

http://www.ruby-doc.org/core-1.9.3/Enumerable.html#method-i-group_by

and

http://www.ruby-doc.org/core-1.9.3/Enumerable.html#method-i-collect

I think they could help.

E.g:

hash = Time.all.collect { |t| [ t.date  , t.hour ] }.group_by { |date,hour|
date.strftime("%-m/%-d/%Y") }

I hope it works.

Regards,
Everaldo

On Sat, Feb 11, 2012 at 11:40 PM, edward michaels <micah...@gmail.com>wrote:

> I have an active record Times table with a date column and an hour
> column.  The hours are unique but the dates can have many hours.  How
> would I create a hash that mapped a date key to its hours?  Something
> like:
>
> hours_per_date['2/14/2012'] => ['6:00', '8:00', '11:00', '2:00']
>
> Thanks
>
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