a = [1,2,3,4,5,6,7,8,9,10] b= a.reverse.reverse On Friday, May 24, 2013 9:56:39 AM UTC-4, Ruby-Forum.com User wrote: > > a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] > b = a + [nil] > p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] > p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil] > > Is there any other Rubyist way to get the `b` array from `a` array? > > -- > Posted via http://www.ruby-forum.com/. >
-- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To unsubscribe from this group and stop receiving emails from it, send an email to rubyonrails-talk+unsubscr...@googlegroups.com. To post to this group, send email to rubyonrails-talk@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/rubyonrails-talk/a96218e0-0aa0-4fe3-b4c6-b8a76d197215%40googlegroups.com?hl=en-US. For more options, visit https://groups.google.com/groups/opt_out.
