Looks to me like you will have an Array of hashes.
The ruby way something like a single line array select
t.select{|tt| a.between?(tt[:min], tt[:max]) && b.between?(tt[:b_min],
tt[:b_max])}
create the array initially with something like
t = Array.new
t << {a_min: 1, a_max:10, b_min: 100, b_max: 1000, p1: 1, p2: 2, p3: 3}
t << {a_min: 1, a_max:10, b_min: 100, b_max: 1000, p1: 1, p2: 2, p3: 3}
(fill in your data)
you could do t = [{your data}, {your hash data}….]
If you only want the first value in the array that matches, use t.detect rather
than t.select
It will return either any array of matching hashes or with detect the first one…
Use the rails console to test all this stuff. rails c
> On Dec 16, 2015, at 3:55 PM, Suo Huang <suo.huang...@gmail.com> wrote:
>
> Hi all,
>
> I am a newbie in Ruby, and I am having a small question with the hash table.
> If anyone could give me some suggestions that would be great!
>
> Considering creating a hash table like this:
>
> a_Min a_Max b_Min b_Max p1 p2 p3
> p4 p5 p6
> 40.000 47.95 -95.0 -74.01 12.8 6.5 177.82
> 0.9150 68.62 0.9020
> 42.000 47.95 -68.0 -59.50 11.0 5.8 185.20
> 0.9377 -11.80 0.9538
> 44.000 47.95 -74.2 -68.05 12.8 6.5 157.45
> 0.9194 37.55 0.9297
> 46.000 66.00 -59.5 -51.00 8.8 3.7 164.96
> 0.9465 -207.54 1.0342
> 47.951 66.00 -79.0 -59.55 12.8 6.5 157.45
> 0.9194 37.55 0.9297
> 47.951 66.00 -95.0 -79.01 12.8 6.5 177.82
> 0.9150 68.62 0.9020
> ...
>
> If giving any (a,b), it will fall within the four boundary control values in
> the hash table (a_Min, a_Max, b_min, b_Max) and returns its relative
> parameters (p1, p2, p3....)
>
> I am trying something like this:
>
> def functionXXX(a, b)
> threshold = XXX # how to create a
> hash table with the above data?
> for t in threshold do
> if (t[:a_Min]<=a && a<t[:a_Max] && t[:b_Min]<=b && b<t[:b_Max])
> then #if there is a smarter way in Ruby for this?
> return t
> break
> end
> end
> end
>
> Would this be the correct way of doing this task in Ruby?
>
> Thanks!
>
> Suo
>
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