I have a find that look likes this: @values = UdidValue.find(:all, :conditions => ['udid_id = ?', x.id], :order => 'value ASC')
The problem is that 'value' could be a street address, for example, numbers. So, when I do the :order if they are strings the get order wonderfully, but in one case I have values that are numbers, for example, 234, 233, 219, 25, 199, which get order as 199, 25, 219, 233, 234. Which is not what I want. I would like to order as 25, 199, 219, 233, 234. Is there a way to get the order to order properly regardless if it is a number of string? Thanks, -S -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk@googlegroups.com To unsubscribe from this group, send email to rubyonrails-talk+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en -~----------~----~----~----~------~----~------~--~---
