thank you for your responses. Actually what I wanted is to show the users based on how many properties they have. Something like @users = User.all(:include => :properties, :order => 'count(properties.id) DESC') If you look it my first post, I have the a statement working for mySql but not in postgre
On Aug 13, 8:52 am, Hassan Schroeder <hassan.schroe...@gmail.com> wrote: > On Thu, Aug 12, 2010 at 11:25 PM, Mohammed Alenazi <vb4...@gmail.com> wrote: > > There is still a problem. > > �...@users = User.paginate :joins => :properties ,:select => 'distinct > > users.*', :page => params[:page], :order => 'properties.id > > DESC',:conditions => ['users.id != 1'] > > I got this error message. > > ActiveRecord::StatementInvalid (PGError: ERROR: for SELECT DISTINCT, > > ORDER BY expressions must appear in select list > > : SELECT distinct users.* FROM "users" INNER JOIN "properties" ON > > properties.user_id = users.id WHERE (users.id != 1) ORDER BY > > properties.id DESC LIMIT 10 OFFSET 0): > > Leaving out pagination and the "users.id != 1" stuff for the moment -- > does something like > @users = User.all(:include => :properties, :order => 'properties.id DESC') > give you the expected data result? > > -- > Hassan Schroeder ------------------------ hassan.schroe...@gmail.com > twitter: @hassan -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-t...@googlegroups.com. To unsubscribe from this group, send email to rubyonrails-talk+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en.
