The original code didn't work because Barney was generating an ActiveRecord
Relation. The .find almost worked, except he wanted to embed Ruby code in a
SQL statement. This should do it:
PeopleSkill.where("people_id = #{@person.id}").find
In the future, I think something like Andrew's suggestion would be a lot
more readable and maintainable--I.E. using ActiveRecord to convert your
database information into objects, and looking for your information among
the objects instead of at the database level.
On Tue, Jul 19, 2011 at 5:17 PM, Andrew Skegg <andrewsk...@me.com> wrote:
> Barney <bsperlin@...> writes:
>
> >
> > Thanks Andrew, but I couldn't make the 'find' work on the
> > 'PeopleSkill.where...' line. When I used 'find' on the @people_skill
> > line it came very close (since in the controller, listed above,
> > people_skill was already choosing the field 'skill'), so when I used:
> > <%= @people_skill.find(@person.id)
> > and skipped the next line listed above, the SQLException was
> > SQLite3::SQLException: near ".": syntax error: SELECT skill FROM
> > "people_skills" WHERE "people_skills"."id" = 23 AND (:people_id =
> > @person.id) LIMIT 1
> > which is VERY close to what I want, except that I want
> > "people_skills"."people_id"=23, not "people_skill"."id"=23. I know
> > that 'find' always looks for the 'id' so I've got to get a different
> > variation.
> > What changes should I make?
> > Thanks again,
> > Barney
>
> What if we flip the logic?
>
> Assuming your models look something like:
>
> Person < ActiveRecord::Base
> has_and_belongs_to_many :skills
> end
>
> Skill < ActiveRecord::Base
> has_and_belongs_to_many :people
> end
>
> With the appropriate PeopleSkills join table in the database.
>
> Then:
>
> @person = Person.find(params[:id])
> @people_skill = @person.skills
>
> Or more easily:
>
> def show
> @person = Person.find(params[:id])
> end
>
> and the view becomes:
>
> <p>
> <b>Skills</b>
> <%= @people.skills >
> </p>
>
> or similar.
>
>
>
>
>
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