On 5/30/14 8:02 AM, Tommi wrote:
The manual says that the precedence of `as` operator is lower than
that of the binary `*` operator. Thus I would not expect the
following to compile (but it does):
let a: u16 = 1; let b: u32 = 2;
let r = a * b as u16;
Since multiplication is supposed to have precedence over casting, I
would expect the last line to be equivalent to:
let r = (a * b) as u16;
...which doesn't compile because `a` and `b` have different types.
Here the compiler clearly first converts `b` to u16 and then
multiplies `a` with the result of that conversion:
let r = a * b as u16;
...but that should happen only if the `as` operator has a higher
precedence than the binary `*` operator.
The precedence of "as" was that way in earlier versions of the language,
but the manual was not updated when the language was changed. This
should be considered a bug in the docs.
Patrick
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