I come from a C# background, so the literal syntax is all new to me. I know about type inference but I am being explicit to demonstrate what I think is a trap for young players :)
let i: i32 = 0_i32; // uses 'i32' on both sides of the declaration let l: u64 = 0_u64; // uses 'u64' on both sides of the declaration let j: int = 0i; // uses 'int' and 'i' which is different on both sides of the declaration On Tue, Nov 4, 2014 at 9:27 AM, Evan G <[email protected]> wrote: > Also, because you have the type information in the variable, there's no > need to redundantly include it by making it an unsigned number literal—rust > can infer that information. > > On Mon, Nov 3, 2014 at 3:25 PM, Evan G <[email protected]> wrote: > >> Not consistent with what? The syntax for number literals is taken >> directly from C/C++, and is used by many other languages. >> >> On Mon, Nov 3, 2014 at 3:19 PM, Jake Scott <[email protected]> wrote: >> >>> I was trying to declare a uint using this: >>> let a: uint = 0_uint; >>> >>> But the correct way to declare it is: >>> let a: uint = 0u; >>> >>> Anyone else think that's not consistent? >>> >>> >>> >>> >>> _______________________________________________ >>> Rust-dev mailing list >>> [email protected] >>> https://mail.mozilla.org/listinfo/rust-dev >>> >>> >> >
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