As a note, with subsets, the behavior of rank is stable under permutations :
sage: S = Subsets([0,1,2],2)
sage: S.unrank(1)
{0, 2}
sage: S.rank([0,2])
1
sage: S.rank([2,0])
1
2011/2/10 Rob Beezer <nicolas.thi...@u-psud.fr>:
> Is the last line a bug, or should the input required to be sorted and
> an error raised? Or am I missing something? The help for rank/unrank
> is not very complete.
>
> sage: C = Combinations([0,1,2], 2)
> sage: C.unrank(1)
> [0, 2]
> sage: C.rank([0,2])
> 1
> sage: C.rank([2,0])
> 0
>
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