On Thu, Dec 13, 2012 at 03:40:47AM -0800, Andrew Mathas wrote:
>    Thanks for the explanation Nicolas. Rather than building a (lazy)
>    dictionary I would have thought that replacing rank() with
>    self._list.index(x) would be the ay to go?

It depends on the size of the set. _list.index(x) has complexity n in
average but has a very small constant. So it's good for small
sets. For larger sets, a dictionary lookup is faster.

We discussed that with Vincent yesterday, and he will probably
implement something with an appropriate threshold.

Cheers,
                                Nicolas
--
Nicolas M. ThiƩry "Isil" <nthi...@users.sf.net>
http://Nicolas.Thiery.name/

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