On Oct 28, 2006, at 10:05 PM, William Stein wrote:
> Regarding ring and algebra elements, suppose x is in a ring R and y > is in a K-algebra S. We want to define what "x * y" means. The > most natural thing to me would be > > x * y is K._coerce_(x) * y > > and that's it. If no coerce map exists, fail. > > Am I missing something? The above rule is definitely easy to > understand. What if you multiply two CommutativeAlgebraElements? You could either attempt the base extension from your previous email, or you could try "forgetting" that the guy on the left is a commutative algebra element, only treat it as a ringElement, and try the coercion you wrote down just above. Could these be different? David --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://sage.scipy.org/sage/ and http://modular.math.washington.edu/sage/ -~----------~----~----~----~------~----~------~--~---
