Le jeudi 6 janvier 2022 à 06:20:28 UTC+1, Jonathan Thornburg a écrit : > I think this problem is worse than "just" a lack of simplification: > if sin(theta) < 0 then sqrt(sin(theta)^2 != sin(theta), i.e., the > theta dependence is wrong, not "just" not-fully-simplified. > > Well, the standard spherical coordinate theta (the colatitude on S^2) lies in [0, pi], so that sin(theta) >= 0. This simplification issue should be dealt either in https://trac.sagemath.org/ticket/33117 (since it seems pretty easy to implement), or in a follow up ticket.
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