On Sun, Apr 16, 2023 at 2:25 AM Michael Orlitzky <mich...@orlitzky.com> wrote:
>
> sage: A = matrix([[-3, 2, 1 ],
> ....: [ 2,-4, 4 ],
> ....: [ 1, 2,-5 ]])
> sage: B = (2 * 0.5 * A)
> sage: B == A
> True
> sage: B.rank() == A.rank()
> False
>
Doesn't this complicates citing sagemath in papers?
e.g. Proof: according \cite{sage} we have A != B, QED.
The testcases appear plausible to me.
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