On Sun, Apr 16, 2023 at 2:25 AM Michael Orlitzky <mich...@orlitzky.com> wrote: >
> sage: A = matrix([[-3, 2, 1 ], > ....: [ 2,-4, 4 ], > ....: [ 1, 2,-5 ]]) > sage: B = (2 * 0.5 * A) > sage: B == A > True > sage: B.rank() == A.rank() > False > Doesn't this complicates citing sagemath in papers? e.g. Proof: according \cite{sage} we have A != B, QED. The testcases appear plausible to me. -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-devel+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sage-devel/CAGUWgD9jnLDZGt7kohZir7K%3DyGYejtJ4keZ3pvoKRC_EXWDo_g%40mail.gmail.com.