Bill Hart wrote:
> 
> 
> On 4 Nov, 03:39, Jason Grout <[EMAIL PROTECTED]> wrote:
>> Bill Hart wrote:
>>> sage: R.<x>=RDF['t']
>>> sage: s=1.0e1*t^3+1.0e-100*t^2+1.01234e-100*t+1.0e1
>>> sage: u=1.0e1*t^3-1.0e1*t^2+1.0e1*t-1.0e1
>>> sage: s*u
>>> 100.0*t^6 - 100.0*t^5 + 100.0*t^4 - 100.0*t^2 + 100.0*t - 100.0
>>> What happened to the t^3 term?
>> Isn't it zero in RDF?
> 
> No. RDF has the possibility to have exponents down to -1023.


I just *knew* I was getting into it over my head and that you knew the 
precision issues at stake.  Sorry for giving you the naive answer; I 
should have realized that of all people, you would know exactly the 
capabilities of machine precision arithmetic!

So I take it your question was really:

Shouldn't Sage realize that the naive computation of the coefficient of 
t^3 is seen as zero, while it is very possible to do the computation in 
such a way that you (correctly) don't get zero?  Shouldn't Sage be smart 
about the precision issues here?

To which I answer: Yes, sure, of course!

It would make for a very interesting demo to show other systems 
incorrectly returning 0 for the coefficient, while Sage is just a bit 
smarter about the arithmetic issues and doesn't return 0.

Mma returns the term as "0. t^3"

Jason


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