On Feb 26, 9:40 pm, Robert Bradshaw <rober...@math.washington.edu>
wrote:
> On Feb 26, 2009, at 12:22 PM, YannLC wrote:
>
> > Hi,
> > am I doing something wrong here?
> > If not, this is a bug...
>
> > sage: f=function('f',x)
> > sage: f
> > f(x)
> > sage: g(f,x)=f(x+1)
> > sage: g
> > (f, x) |--> x + 1
>
> When one writes g(f, x) it creates two variables f and x, and your
> original f is gone. I'm not sure what the best fix is here... There
> is also the counter-intuitive
>
> sage: f = var('f')
> sage: f(3)
> 3
>
> - Robert
My point was unclear.
* First, how to define a function 'g' doing what I want then? I mean
with an argument which is a function; is it possible?
* then, I think that f shouldn't disappear like this:
sage: g(f,x)=f(x)
sage: g
(f, x) |--> x
Yann
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