In number theory it is very useful to have this norm-alisation, as well as the square root one also called abs. It's a special case of the algebraic concept of norm(a) = product of conjugates of a.
If this was really a problem to non-number-theorists, we could possibly live with it (possibly by defining a new function for this). Other opinions may differ... John On 26 April 2010 20:21, Jason Grout <jason-s...@creativetrax.com> wrote: > Why does Sage say the norm of a complex number a+b*I is a^2+b^2? > > > sage: norm(1+2*I) > 5 > > > In MMA: > > In[1]:= Norm[1+2*I] > > Out[1]= Sqrt[5] > > Wikipedia and mathworld both agree that the norm should be sqrt(5) (i.e., > the square root of the number times its conjugate). > > Note that abs() seems right: > > sage: abs(1+2*I) > sqrt(5) > > Thanks, > > Jason > > -- > To post to this group, send an email to sage-devel@googlegroups.com > To unsubscribe from this group, send an email to > sage-devel+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/sage-devel > URL: http://www.sagemath.org > -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
