The easiest way to get the number of digits of a positive integer n is len(str(n)) or even n.ndigits() !
So sage: N=10^6 sage: sum([n.ndigits() for n in srange(1,N+1)]) 5888896 solves your problem for all integers up to a million. This is obviously not the fastest way though! John On Apr 9, 6:53 pm, Alex Howard <ajhowar...@gmail.com> wrote: > Hi, > I'm trying to create a function which outputs the number of digits you'd have > to > write down to write every integer from 1 up to the input value. > Having defined x and z as variables I used this at one point... > > z(x)=((int(log(x,10)))+1)*(1+x-((10^int(log(x,10))))) > > It gets rejected as does using the 'floor' function. At one point i managed to > make it output > > z(3143) = ((floor(log(3143,10)))+1)*(1+3143-((10^floor(log(3143,10))))) > > as an expression involving logs but I can't find a way to output a number. any > help would be great. > > Thanks -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
