Via "n??" I looked at the code. There is a line prec = int((digits+1) * 3.32192) + 1 where the 3.32… is an approximation to log_2(10). I highly suspect that's the source of it. Make the trailing 2 a 3 and it should give you more than the requested number of digits.
sage: n(log(10,2), prec=100) 3.3219280948873623478703194295… H -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
