Hi,

On Tuesday 03 Jul 2012, Simon King wrote:
> Hi!
> 
> On 2012-07-02, Martin Albrecht <[email protected]> wrote:
> > Shouldn't both give the same distribution mod p? Since every non-singular
> > matrix A has a LU decomposition we should be able to just sample L and U
> > separately to produce A?
> 
> Sorry for my ignorance, but is it really the case that an LU
> decomposition exists for all invertible matrices? I thought there may
> only be an LUP decomposition.

Argh, yes, you're right: should be LUP.

> If I am not mistaken, the LU decomposition is unique if one requires
> that L (or U) has only 1 on the diagonal. Because of the uniqueness, I'd
> expect that putting 1 on the diagonal of L and choosing the entries of U
> and the remaining of L randomly equally distributed yields a reasonable
> distribution of invertible matrices.
> 
> However, if it is really the case that we must consider LUP
> decompositions, then I am not totally convinced that a nicely distributed
> random choice of a permutation matrix P on top of the choice of L and U as
> above yields a nice distribution of invertible matrices.

Mhh, why not? If A = LUP we just write AP^-1  = LU, hence for each LU we 
construct there are as many As as there are permutation matrices, or am I 
missing something (again :))?

Cheers,
Martin

--
name: Martin Albrecht
_pgp: http://pgp.mit.edu:11371/pks/lookup?op=get&search=0x8EF0DC99
_otr: 47F43D1A 5D68C36F 468BAEBA 640E8856 D7951CCF
_www: http://martinralbrecht.wordpress.com/
_jab: [email protected]

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