On 2017-09-06 17:24, Erik Bray wrote:
Interpreting
"str" as "bytes" is the only way it can be if language_level=2.
I think you are misunderstanding. You didn't post the complete C code
generated by Cython:
__pyx_t_4 = __Pyx_PyBytes_FromString(__pyx_v_s); if
(unlikely(!__pyx_t_4)) __PYX_ERR(0, 2076, __pyx_L1_error)
__Pyx_GOTREF(__pyx_t_4);
__pyx_t_3 = PyTuple_New(1); if (unlikely(!__pyx_t_3)) __PYX_ERR(0,
2076, __pyx_L1_error)
__Pyx_GOTREF(__pyx_t_3);
__Pyx_GIVEREF(__pyx_t_4);
PyTuple_SET_ITEM(__pyx_t_3, 0, __pyx_t_4);
__pyx_t_4 = 0;
__pyx_t_4 = __Pyx_PyObject_Call(((PyObject *)(&PyString_Type)),
__pyx_t_3, NULL); if (unlikely(!__pyx_t_4)) __PYX_ERR(0, 2076,
__pyx_L1_error)
__Pyx_GOTREF(__pyx_t_4);
__Pyx_DECREF(__pyx_t_3); __pyx_t_3 = 0;
__pyx_v_k = __pyx_t_4;
__pyx_t_4 = 0;
So, what this does is to interpret a char* as bytes, because a char*
really is just bytes. And then it calls str() on the result. So you get
str(b"1").
I don't think that this has anything to do with the language_level.
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