On Wed, May 30, 2018 at 8:14 AM, Travis Scrimshaw <tsc...@ucdavis.edu> wrote:
>
>
> On Tuesday, May 29, 2018 at 9:01:51 PM UTC+10, chris wuthrich wrote:
>>
>>
>> As a simple-minded user I stumbled over exactly this last week. I don't
>> understand much of what this thread is discussing, but I know what a
>> simple-minded user wants.
>>
>> sage: G = GL(2,13)
>> sage: G = G.as_matrix_group()
>> sage: H = G.subgroup([ matrix(GF(13),[[1,0],[1,1]]) ])
>> sage: H2 = G.subgroup([ matrix(GF(13),[[1,1],[0,1]]) ])
>> sage: H3 = G.subgroup([ matrix(GF(13),[[1,0],[2,1]]) ])
>>
>> I expect H == H3 to say True as they are the same subgroup.
>> I expect H = H2 to say False, since they are not the same subgroup, even
>> though they are isomorphic.
>> Instead
>>
>> sage: H == H3
>> False
>> sage: matrix(GF(13),[[1,0],[1,1]]) in H3
>> True
>> sage: matrix(GF(13),[[1,0],[2,1]]) in H
>> True
>> sage: H.is_isomorphic(H3)
>> True
>> sage: H.is_isomorphic(H2)
>> True
>> sage: matrix(GF(13),[[1,0],[1,1]]) in H2
>> False
>>
>> I though of working around it by checking if they are the same as sets,
>> but to my surprise:
>>
>> sage: Set( h for h in H ) == Set( h for h in H3 )
>> False
>> sage: Set( h.matrix() for h in H ) == Set( h.matrix() for h in H3 )
>> True
>>
>> In short: I consider this a bug. No matter how this is done at the back,
>> the user expects == to mean mathematical equality, here equality of
>> subgroups. Otherwise the function should be called
>> subgroups_with_given_generators.

"mathematical equality" is also a red herring being that there are
many possible definitions thereof.  Are we talking equality up to
isomorphism? Etc...

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