On Saturday, November 30, 2019 at 5:10:48 PM UTC-8, vdelecroix wrote: > > > Calling c.minpoly() triggers some exactification. Compare with > > sage: a = AA(2).sqrt() > sage: b = AA(3).sqrt() > sage: (a + b) * (a - b) * (b - a) * (-a -b) > 1.000000000000000? > Sure, but there is no "numerical noise" other than in the internal interval arithmetic and perhaps a little strange printing. In all cases, the quantity computed is exactly 1.
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