PS. Sorry, copy-paste error, I missed out the first line of the example,
which was the usual incantation "sage: R.<x> = PolynomialRing(QQ)".

On Thu, 25 Nov 2021 at 13:26, David Loeffler <[email protected]>
wrote:

> If I have two elliptic curves over a number field, then Sage seems to know
> how to test if they are isogenous, and find the minimal degree of an
> isogeny between them; but is there any way of computing the actual isogeny?
>
> Here's an example (the Q-curve 45.1-a1 over Q(sqrt(5)) and its Galois
> conjugate):
>
> sage: K.<a> = NumberField(R([-1, -1, 1]))
> sage: E =
> EllipticCurve([K([0,1]),K([1,1]),K([1,0]),K([-7739,-4364]),K([-296465,-255406])])
> sage: si = K.Hom(K).list()[-1]
> sage: E2 = E.base_extend(si)
> sage: E.is_isogenous(E2)
> True
> sage: E.isogeny_degree(E2)
> 4
>
> There is a method "E.isogeny(...)" but it wants an explicit kernel. The
> docstring says that the kernel will be computed automatically if I specify
> "kernel=None", but that seems to result in an error:
>
> sage: E.isogeny(kernel=None, codomain=E2, degree=4)
> [...]
> ValueError: The two curves are not linked by a cyclic normalized isogeny
> of degree 4
>
> I'm not sure what "normalized" means here, but there is definitely a
> cyclic degree 4 isogeny from E to E2. What do I need to do to persuade Sage
> to find it?
>
> Regards, David
>
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