Are you sure that you need Tuple() at all for what you are doing? Try looking at the documentaion for it with Tuples? If all you want to do is count the number of times an element appears in a list, use the count() function which every lisy has, like this
sage: u=[1+I,1+I,1+I,2+I,2+I,2+I,2+I] sage: u.count(1+I) 3 sage: u.count(2+I) 4 John Cremona 2008/5/9 Rose <[EMAIL PROTECTED]>: > > Hi, > > (I am a Newbie) > I need to count complex number in Tuples and the only way I found out > is to use Tuples(l,1).count() or UnorderedTuples(l,1).count() (I don't > understand the difference), but I have two problems. > > First, it counts only once an element that is twice in my Tuples. > ex: sage: u=[1,2,1] > sage: Tuples(u,1).count() > 2 > > Second, it becomes pretty long went there are complex numbers in my > Tuples (more than 30 secondes for 7 elements). > > I would like to know if there is a better way to count a Tuples of > complex number. > > In general, it is really long when I utilize Tuples with complex > number (in comparaison of doing 2 Tuples, one for real part and one > for imaginary part). > > > > --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
