On Sun, Nov 30, 2008 at 3:41 PM, David Joyner <[EMAIL PROTECTED]> wrote:
> It's been awhile since I used Maple and I still don't understand your
> question.
> Is it possible to copy+paste a Maple session in and then just ask
> "can this be done in sage"?
To clarify my own question, one can do the following manipulations
sage: t,s = var('t,s')
sage: x = function('x', t)
sage: de = diff(x,t) + 2*x == t
sage: laplace(de.left(),t,s) == laplace(de.right(),t,s)
s*laplace(x(t), t, s) + 2*laplace(x(t), t, s) - x(0) == 1/s^2
but I guess this is not what is requested. I'm wondering what type of
manipulation Pieter needs.
>
> On Sun, Nov 30, 2008 at 11:21 AM, pieter <[EMAIL PROTECTED]> wrote:
>>
>> Dear Simon,
>>
>> Thanks for your answer.
>>
>> What I want is for a linear combination X(t):=p(t)*y1(t) + q(t)*y2(t)
>> (p and q are known functions) to construct a new
>> second-order differential equation for X(t) from the orgininal
>> system. For a second-order system this can easily be done by hand.
>> I have, however, a fourth-order system.
>> I have written a Maple-program to perform this task for the fourth-
>> order system.
>> I wonder if this can be done with Sage.
>>
>> Regards,
>> Pieter
>>
>>
>> On Nov 27, 5:29 pm, Simon King <[EMAIL PROTECTED]> wrote:
>>> Dear David,
>>>
>>> On Nov 27, 5:16 pm, "David Joyner" <[EMAIL PROTECTED]> wrote:
>>>
>>> > Do you mean something like in the
>>> > tutorialhttp://www.sagemath.org/doc/tut/node14.html
>>> > or do you want something different?
>>>
>>> Looking at the original post, probably Pieter wants to manipulate y1
>>> (t), y2(t) without to solve the system of equations, since this is
>>> possible with Maple, to some extent:
>>>
>>> > > In Maple it is possible to manipulate with y1(t) and y2(t) without
>>> > > solving the system of equations.
>>>
>>> > > Does there exist a Sage-construct equivalent to the Maple-construct
>>> > > given above?
>>>
>>> So, I guess it is different fromhttp://www.sagemath.org/doc/tut/node14.html
>>>
>>> Cheers,
>>> Simon
>> >>
>>
>
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