I think the order of the i and j is transposed (assuming row i and column j): sage: M = matrix(5,5,[[1/(i+j%2) for j in range(1,6)] for i in range (1,6)]) sage: M
[1/2 1 1/2 1 1/2] [1/3 1/2 1/3 1/2 1/3] [1/4 1/3 1/4 1/3 1/4] [1/5 1/4 1/5 1/4 1/5] [1/6 1/5 1/6 1/5 1/6] s M = matrix(5,5,[[1/(i+j%2) for j in range(1,6)] for i in range(1,6)]) On Dec 10, 4:24 pm, "David Joyner" <[EMAIL PROTECTED]> wrote: > One way to do it (for a 10x10): > > sage: n = 10 > sage: M = Matrix(n,n,[[1/(i+j) for i in range(1,11)] for j in range(1,11)]) > sage: M > > [ 1/2 1/3 1/4 1/5 1/6 1/7 1/8 1/9 1/10 1/11] > [ 1/3 1/4 1/5 1/6 1/7 1/8 1/9 1/10 1/11 1/12] > [ 1/4 1/5 1/6 1/7 1/8 1/9 1/10 1/11 1/12 1/13] > [ 1/5 1/6 1/7 1/8 1/9 1/10 1/11 1/12 1/13 1/14] > [ 1/6 1/7 1/8 1/9 1/10 1/11 1/12 1/13 1/14 1/15] > [ 1/7 1/8 1/9 1/10 1/11 1/12 1/13 1/14 1/15 1/16] > [ 1/8 1/9 1/10 1/11 1/12 1/13 1/14 1/15 1/16 1/17] > [ 1/9 1/10 1/11 1/12 1/13 1/14 1/15 1/16 1/17 1/18] > [1/10 1/11 1/12 1/13 1/14 1/15 1/16 1/17 1/18 1/19] > [1/11 1/12 1/13 1/14 1/15 1/16 1/17 1/18 1/19 1/20] > > On Wed, Dec 10, 2008 at 5:19 PM, Alasdair <[EMAIL PROTECTED]> wrote: > > > The title pretty much says it all - for example, how would I create a > > 4x4 matrix whose (i,j)-th element is 1/(i+j)? > > > Thanks, > > Alasdair --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
