Thank you very much
On May 6, 7:47 pm, Robert Bradshaw <rober...@math.washington.edu>
wrote:
> On May 6, 2009, at 7:44 PM, jimfar wrote:
>
> > After generating
> > sage: B=AlternatingGroup(5)
>
> > and verifying an element is in it,
> > sage: c=(1,2,3)
> > sage: c in B
> > True
>
> > How do I find the inverse of c in B?
>
> Your c here isn't really a permutation element, it's just a tuple. To
> create (and manipulate) the actual permutation element do:
>
> sage: c = B((1,2,3)); c
> (1,2,3)
> sage: c^-1
> (1,3,2)
> sage: c^2
> (1,3,2)
> sage: parent(c)
> Alternating group of order 5!/2 as a permutation group
>
> - Robert
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