On Tue, May 19, 2009 at 9:13 AM, Greg <ggdhi...@gmail.com> wrote: > > Hi, I have a set of data that I want to create a contour plot for. > Since I have the data and not the function that created the data, I > cannot use contour_plot. Matplotlib has a function "contour" that > accepts a vector of data and does exactly what I want expect I cannot > get it to work in Sage notebook. > > I tried using the example given on the Matplotlib webpage which > amounts to: > import matplotlib.pyplot as plt > plt.contour(Z) > plt.show() > > (where Z is my data). However nothing shows up. Any suggestions? > > thanks, Greg
Here is an example from the Sage reference manual on how to use matplotlib from sage: sage: from pylab import * sage: t = arange(0.0, 2.0, 0.01) sage: s = sin(2*pi*t) sage: P = plot(t, s, linewidth=1.0) sage: xl = xlabel('time (s)') sage: yl = ylabel('voltage (mV)') sage: t = title('About as simple as it gets, folks') sage: grid(True) sage: savefig('sage.png') William --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---