Hi all,
I'm afraid this question has already appeared in this forum, but here it goes
again.
I'm curious about why the inverse_laplace() function can't successfully invert
some
well-known, nevertheless rather simple, functions. Let's take exp(-as)/s as an
example, whose inverse is the Heaviside function H(t-a):
var('s,t')
f = (exp(-s)/s).inverse_laplace(s,t); f
The evaluation of the second line produces:
ilt(e^(-s)/s, s, t)
Which, obviously, is not a satisfactory answer. What happens here?
How does inverse_laplace() work?
Regards,
Fausto
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