Perhaps working in the symbolic ring is causing something you don't like. In David's example above, you might want to convert things to CDF, which gives:
sage: a = CDF(1 + 3*I) sage: z = log(a) sage: z 1.1512925465 + 1.2490457724*I ...instead of sage: a = 1 + 3*I sage: z = log(a) sage: z log(3*I + 1 But its hard to guess unless you give more details about what you are doing. -M.Hampton On Jul 6, 10:52 am, David Joyner <wdjoy...@gmail.com> wrote: > On Mon, Jul 6, 2009 at 12:25 PM, mac8090<bonzerpot...@hotmail.com> wrote: > > > when I try to take logarithms of a complex number sage version 3.5 > > doesn't like it. How do I find/use a multiplication preserving > > embedding to make it work? > > I don't understand the question. In the latest version you get this: > > sage: a = 1 + 3*I > sage: z = log(a) > sage: z.real() > log(sqrt(10)) > sage: z.imag() > arctan(3) > > Is that what you want? > > --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
