isqrt returns the integer part (floor) of a square root.
On Jul 17, 7:33 am, Santanu Sarkar <sarkar.santanu....@gmail.com> wrote: > Thank you. > > 2009/7/16 Marshall Hampton <hampto...@gmail.com> > > > > > > > I'm not quite sure what you want, but for example > > > sage: B = sqrt(1000) > > sage: floor(B) > > 31 > > > would give you the integer part (rounded down since its floor). The > > round() function might be what you want instead (round(B) is 32.0). > > > -Marshall Hampton > > > On Jul 16, 10:05 am, Santanu Sarkar <sarkar.santanu....@gmail.com> > > wrote: > > > Suppose we want to find just integer part of square root 1000. Say > > > B=sqrt(1000). Then how can I use digits function i,e. B.digits() to find > > the > > > bits of B. --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
