Dear Michael and Minh, > > > So I'm assuming that the documentation is outdated. Maybe this > > is well know, but I hope it is ok to post this here. > > Could you try the examples in the documentation at [1] and see if it's > what you wanted? > > [1]http://www.sagemath.org/doc/reference/sage/misc/functional.html#sage.... > > -- > Regards > Minh Van Nguyen
Great! I have seen in the documentation of [1], and I have seen the notation sum(1/k^4, k, 1, oo) that is also new for me. But I want to make a comment, also from this documentation. It says sum(1/(1+k^2), k, -oo, oo, algorithm = 'mathematica') # optional -- requires mathematica OK, I understand that sage do not kown how to evaluate sum(1/(1+k^2), k, -oo, oo) But it answer 0 , that is wrong!!! (I have yet 4.3.1; I'm waiting 4.3.4 to update my sage) Yours, Juan Luis Varona -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org To unsubscribe from this group, send email to sage-support+unsubscribegooglegroups.com or reply to this email with the words "REMOVE ME" as the subject.
